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How does Ant <xslt> accept 2 input files such that xsl could differentiate them ?

Z W

2008-03-22

Replies:
Hi

How do I make an ant <xslt> call that accepts 2 different input xml
files in different directories
such that the xsl could know which file with for-each to perform calculations.


Inside y.xsl
<xsl:for-each select="/testResults/*[not(@(protected))]">

From Ant x.xml file
<xslt style="detail.xsl"
              in="C:\test_report\test_input_3.jtl"
              destdir="C:\test_report"
              basedir="C:\test_report"
              out="C:\test_input_3.html"
              force="true">
              <param name="currentJTL"
expression="C:\test_report\test_input_3.jtl"/>
              <param name="previousJTL"
expression="C:\test_input.jtl"/>
              <param name="curBuildVersion"
expression="${currentBuildVersion}"/>
              <param name="pBuildVersion"
expression="${previousBuildVersion}"/>
              <param name="latestDir"
expression="${Detail_latestTPSDir}"/>
              <classpath
location="C:\apache-ant-1.7.0\lib\saxon9.jar" />

Is there a way where I could include with for-each specifying to
include a specific file.
I want to make use of currentJTL and previousJTL as you can see above
in Ant xml file but
the xsl could only interpret file from in="C:\test_report\test_input_3.jtl".

thank you for your help

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